腾讯极客技术挑战赛第三期码上种树Writeup
前言
第一次参加网安相关的竞赛，种了一百万课数（因为要上课，只做了一天半）。看大佬们都在写Writeup（查了下意思是 ctf（信息安全夺旗赛）中的解题思路），我也来搞一篇，记录一下我的解题思路和学到<的东西（好多东西是第一次见）。
题目
第一题
第一题是直接把第一个请求返回的参数在发送出去。
def main():
url = "http://159.75.70.9:8081/pull?u=000003315146DEE5E425871CDE778FF5"
postData = "u=000003315146DEE5E425871CDE778FF5"
try:
r = requests.post(url, data=postData)
t = json.loads(r.text)["t"]
a = json.loads(r.text)["a"]
c = json.loads(r.text)["c"]
url1 = "http://159.75.70.9:8081/push?t=" + t + "&a=" + a
r1 = requests.get(url1, timeout=0.5)
print(r1.text)
except Exception as e:
print(e)
if __name__ == "__main__":
while True:
main()第二题
第二题题目JS文件:
window.A3C2EA99=async function({a}){return new Promise(_=>setTimeout(__=>_(a[0]*a[0]+a[0]),2000))}一个简单计算，只是加了一个定时器，这个题感觉直接在浏览器上修改就可以，但是我为了以后的题，统一使用的python。
def main():
url = "http://159.75.70.9:8081/pull?u=000003315146DEE5E425871CDE778FF5"
postData = "u=000003315146DEE5E425871CDE778FF5"
try:
r = requests.post(url, data=postData)
t = json.loads(r.text)["t"]
a = int(json.loads(r.text)["a"])
c = json.loads(r.text)["c"]
a = str(a*a+a)
url1 = "http://159.75.70.9:8081/push?t=" + t + "&a=" + a
r1 = requests.get(url1, timeout=0.5)
print(r1.text)
except Exception as e:
print(e)
if __name__ == "__main__":
while True:
main()第三题
第三题JS文件
eval(atob("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"))搜了一下atob()，发现 atob() 方法用于解码使用 base-64 编码的字符串 。
Base64解码，格式化代码后：
var _0xe936 = ['A5473788']; (function(_0x48e85c, _0xe936d8) {
var _0x23fc5a = function(_0x2858d9) {
while (--_0x2858d9) {
_0x48e85c['push'](_0x48e85c['shift']());
}
};
_0x23fc5a(++_0xe936d8);
} (_0xe936, 0x196));
var _0x23fc = function(_0x48e85c, _0xe936d8) {
_0x48e85c = _0x48e85c - 0x0;
var _0x23fc5a = _0xe936[_0x48e85c];
return _0x23fc5a;
};
window[_0x23fc('0x0')] = function(_0x335437) {
var _0x1aac02 = 0x30d3f;
for (var _0x3bed6a = 0x30d3f; _0x3bed6a > 0x0; _0x3bed6a--) {
var _0x375340 = 0x0;
for (var _0x1ddb77 = 0x0; _0x1ddb77 < _0x3bed6a; _0x1ddb77++) {
_0x375340 += _0x335437['a'][0x0];
}
_0x375340 % _0x335437['a'][0x2] == _0x335437['a'][0x1] && _0x3bed6a < _0x1aac02 && (_0x1aac02 = _0x3bed6a);
}
return _0x1aac02;
};最后通过变量替换得到解决代码：
i1 = 199999
value = 199999
while i1 > 0:
temp_val = 0
i2 = 0
while i2 < i1:
temp_val = a[0] + temp_val
i2 = i2 + 1
if i1 % 100 == 0:
temp_val = i1 * a[0]
if temp_val % a[2] == a[1]:
if i1 < 199999:
value = i1
i1 = i1 - 1
a = value第四题
题目JS文件
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new 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然后把那些“!+[]”等放到浏览器中计算，然后进行变量替换得到：
window.A593C8B8 = async (A) => (($, A, B, C, D) => {
let E = function* () {
while (1) yield[(A, B) => A + B, (A, B) => A - B, (A, B) => A * B][++B % 3]["bind"](0, C, D)
}();
let F = function (E, F, G) {
D = E;
C = F["next"]()["value"]();
B == A["a"]["length"] && G(-C)
};
let temp = new Promise(B => A["a"]["forEach"](C => $["setTimeout"](D => F(C, E, B), C)))
return temp
})(window, A, 0, 0, 0)通过分析代码和观察数据得出这其实就是先把A中的数据排序，然后按照固定加减乘次序做一次运算。
这里浪费了我好长时间，看来以后得重视使用浏览器开发者工具调试。
解题代码关键部分：
temArr = a
for i in range(6):
temArr.append(a[i])
temArr.sort()
tempVal = (temArr[0] * temArr[1] - temArr[2] + temArr[3]) * temArr[4] - temArr[5] + temArr[6]第五题
题目JS文件：
window.A661E542 = async function ({
a: A
}) {
return (await WebAssembly.instantiate(
await WebAssembly.compile(await (
await fetch("data:application/octet-binary;base64,AGFzbQEAAAABBwFgAn9/AX8CFwIETWF0aANtaW4AAARNYXRoA21heAAAAwIBAAcHAQNSdW4AAgpgAV4BBn8gACECIAFBAWsiBARAA0AgAiEDQQAhBkEKIQcDQCADQQpwIQUgA0EKbiEDIAUgBhABIQYgBSAHEAAhByADQQBLDQALIAIgBiAHbGohAiAEQQFrIgQNAAsLIAIL")).arrayBuffer()), {
Math: Math
})).exports.Run(...A)
}Data部分解密之后得到：
00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F
--------------------------------------------------------------------
00 61 73 6D 01 00 00 00 01 07 01 60 02 7F 7F 01 | .asm.......`..
7F 02 17 02 04 4D 61 74 68 03 6D 69 6E 00 00 04 | ....Math.min...
4D 61 74 68 03 6D 61 78 00 00 03 02 01 00 07 07 | Math.max........
01 03 52 75 6E 00 02 0A 60 01 5E 01 06 7F 20 00 | ..Run...`.^.. .
21 02 20 01 41 01 6B 22 04 04 40 03 40 20 02 21 | !. .A.k"..@.@ .!
03 41 00 21 06 41 0A 21 07 03 40 20 03 41 0A 70 | .A.!.A.!..@ .A.p
21 05 20 03 41 0A 6E 21 03 20 05 20 06 10 01 21 | !. .A.n!. . ...!
06 20 05 20 07 10 00 21 07 20 03 41 00 4B 0D 00 | . . ...!. .A.K..
0B 20 02 20 06 20 07 6C 6A 21 02 20 04 41 01 6B | . . . .lj!. .A.k
22 04 0D 00 0B 0B 20 02 0B | "..... ..好家伙又是没见到过的东西。
去搜了一下。
WebAssembly（缩写为 Wasm）是基于堆栈的虚拟机的二进制指令格式。Wasm 被设计为编程语言的可移植编译目标，从而可以在 Web 上为客户端和服务器应用程序进行部署。
- 高效快捷：Wasm stack machine 设计为以节省大小和加载时间的二进制格式进行编码。WebAssembly旨在通过利用广泛平台上可用的通用硬件功能，以本机速度执行。
- 安全的：WebAssembly描述了一种内存安全的沙盒执行环境，该环境甚至可以在现有JavaScript虚拟机内部实现。当嵌入到Web中时，WebAssembly将强制执行浏览器的同源和权限安全策略。
- 开放且可调试：WebAssembly设计为以文本格式精美打印，用于手工调试，测试，实验，优化，学习，教学和编写程序。在Web上查看Wasm模块的来源时，将使用文本格式。
- 开放式网络平台的一部分：WebAssembly旨在维护Web的无版本，经过功能测试和向后兼容的性质。WebAssembly模块将能够调用和退出JavaScript上下文，并通过可从JavaScript访问的相同Web API来访问浏览器功能。WebAssembly还支持非Web嵌入。
搞了一下午了反汇编，得到：
(module
(func $Math.min (;0;) (import "Math" "min") (param i32 i32) (result i32))
(func $Math.max (;1;) (import "Math" "max") (param i32 i32) (result i32))
(func $Run (;2;) (export "Run") (param $var0 i32) (param $var1 i32) (result i32)
(local $var2 i32) (local $var3 i32) (local $var4 i32) (local $var5 i32) (local $var6 i32) (local $var7 i32)
local.get $var0
local.set $var2
local.get $var1
i32.const 1
i32.sub
local.tee $var4
if
loop $label1
local.get $var2
local.set $var3
i32.const 0
local.set $var6
i32.const 10
local.set $var7
loop $label0
local.get $var3
i32.const 10
i32.rem_u
local.set $var5
local.get $var3
i32.const 10
i32.div_u
local.set $var3
local.get $var5
local.get $var6
call $Math.max
local.set $var6
local.get $var5
local.get $var7
call $Math.min
local.set $var7
local.get $var3
i32.const 0
i32.gt_u ;; a0 > 0
br_if $label0
end $label0
local.get $var2
local.get $var6
local.get $var7
i32.mul ;; v6*v7
i32.add
local.set $var2
local.get $var4
i32.const 1
i32.sub
local.tee $var4
br_if $label1
end $label1
end
local.get $var2
)
)
好吧，看不懂这些指令，去学了wasm及其指令集，之后用python写了一下这个算法，不过奇怪的事情发现了，答案有时候对，有时候不对。奇怪的很！
two hour later ~
偶然间发现浏览器开发者工具中的source不但可以直接得到反汇编后的代码，而且可以设断点，进行调式。
然后进行了优化，很快得到了正确解题代码：
v0 = a[0]
v1 = a[1]
v2 = v0
v3 = 0
v4 = v1 - 1
v5 = 0
if v4 > 0:
while True:
v3 = v2
v6 = 0
v7 = 10
while True:
v5 = v3 % 10
v3 = int(v3 / 10)
6 = max(v5, v6)
v7 = min(v5, v7)
if v3 <= 0:
break
v2 = v2 + v6 * v7
v4 = v4 - v1
if v4 <= 0:
break
a = str(v2)
空空如也！